7x^2+56x+12=0

Solution for 7x^2+56x+12=0 equation:

7x^2+56x+12=0

a = 7; b = 56; c = +12;
Δ = b2-4ac
Δ = 562-4·7·12
Δ = 2800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2800}=\sqrt{400*7}=\sqrt{400}*\sqrt{7}=20\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-20\sqrt{7}}{2*7}=\frac{-56-20\sqrt{7}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+20\sqrt{7}}{2*7}=\frac{-56+20\sqrt{7}}{14}
$